Distance from Agios Ioannis Rentis to Jacksonville
The shortest distance (air line) between Agios Ioannis Rentis and Jacksonville is 5,699.68 mi (9,172.74 km).
How far is Agios Ioannis Rentis from Jacksonville
Agios Ioannis Rentis is located in Peiraias; Nisoi, Greece within 37° 58' 0.12" N 23° 40' 0.12" E (37.9667, 23.6667) coordinates. The local time in Agios Ioannis Rentis is 14:31 (25.12.2025)
Jacksonville is located in Florida, United States within 30° 19' 55.92" N -82° 19' 30.36" W (30.3322, -81.6749) coordinates. The local time in Jacksonville is 07:31 (25.12.2025)
The calculated flying distance from Jacksonville to Jacksonville is 5,699.68 miles which is equal to 9,172.74 km.
Agios Ioannis Rentis, Peiraias; Nisoi, Greece
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Jacksonville, Florida, United States