Distance from Alachua to Jefferson Valley-Yorktown
The shortest distance (air line) between Alachua and Jefferson Valley-Yorktown is 933.70 mi (1,502.64 km).
How far is Alachua from Jefferson Valley-Yorktown
Alachua is located in Florida, United States within 29° 46' 40.44" N -83° 31' 0.48" W (29.7779, -82.4832) coordinates. The local time in Alachua is 18:21 (02.01.2026)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 18:21 (02.01.2026)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 933.70 miles which is equal to 1,502.64 km.
Alachua, Florida, United States
Related Distances from Alachua
Jefferson Valley-Yorktown, New York, United States