Distance from Alachua to Sannicolau Mare
The shortest distance (air line) between Alachua and Sannicolau Mare is 5,335.50 mi (8,586.65 km).
How far is Alachua from Sannicolau Mare
Alachua is located in Florida, United States within 29° 46' 40.44" N -83° 31' 0.48" W (29.7779, -82.4832) coordinates. The local time in Alachua is 17:37 (02.03.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 00:37 (03.03.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 5,335.50 miles which is equal to 8,586.65 km.
Alachua, Florida, United States
Related Distances from Alachua
Sannicolau Mare, Timiş, Romania