Distance from Albany to Celakovice
The shortest distance (air line) between Albany and Celakovice is 3,996.19 mi (6,431.25 km).
How far is Albany from Celakovice
Albany is located in New York, United States within 42° 39' 59.04" N -74° 12' 4.68" W (42.6664, -73.7987) coordinates. The local time in Albany is 16:16 (12.02.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 22:16 (12.02.2025)
The calculated flying distance from Celakovice to Celakovice is 3,996.19 miles which is equal to 6,431.25 km.
Albany, New York, United States
Related Distances from Albany
Celakovice, Středočeský kraj, Czechia