Distance from Albany to Sveti Ivan Zelina
The shortest distance (air line) between Albany and Sveti Ivan Zelina is 4,205.62 mi (6,768.29 km).
How far is Albany from Sveti Ivan Zelina
Albany is located in New York, United States within 42° 39' 59.04" N -74° 12' 4.68" W (42.6664, -73.7987) coordinates. The local time in Albany is 14:49 (12.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 20:49 (12.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,205.62 miles which is equal to 6,768.29 km.
Albany, New York, United States
Related Distances from Albany
Sveti Ivan Zelina, Zagrebačka županija, Croatia