Distance from Aleksandrow Kujawski to Alexandroupoli
The shortest distance (air line) between Aleksandrow Kujawski and Alexandroupoli is 896.32 mi (1,442.49 km).
How far is Aleksandrow Kujawski from Alexandroupoli
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:02 (28.05.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 07:02 (28.05.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 896.32 miles which is equal to 1,442.49 km.
Aleksandrow Kujawski, Włocławski, Poland