Distance from Aleksandrow Kujawski to Bad Segeberg
The shortest distance (air line) between Aleksandrow Kujawski and Bad Segeberg is 352.29 mi (566.96 km).
How far is Aleksandrow Kujawski from Bad Segeberg
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 11:56 (10.05.2025)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 11:56 (10.05.2025)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 352.29 miles which is equal to 566.96 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Bad Segeberg, Segeberg, Germany