Distance from Aleksandrow Kujawski to Cesky Tesin
The shortest distance (air line) between Aleksandrow Kujawski and Cesky Tesin is 216.32 mi (348.14 km).
How far is Aleksandrow Kujawski from Cesky Tesin
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:54 (03.12.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 04:54 (03.12.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 216.32 miles which is equal to 348.14 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Cesky Tesin, Moravskoslezský kraj, Czechia