Distance from Aleksandrow Kujawski to Cesson-Sevigne
The shortest distance (air line) between Aleksandrow Kujawski and Cesson-Sevigne is 946.74 mi (1,523.63 km).
How far is Aleksandrow Kujawski from Cesson-Sevigne
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:48 (04.05.2025)
Cesson-Sevigne is located in Ille-et-Vilaine, France within 48° 7' 14.88" N -2° 23' 47.04" W (48.1208, -1.6036) coordinates. The local time in Cesson-Sevigne is 09:48 (04.05.2025)
The calculated flying distance from Cesson-Sevigne to Cesson-Sevigne is 946.74 miles which is equal to 1,523.63 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Cesson-Sevigne, Ille-et-Vilaine, France