Distance from Aleksandrow Kujawski to Clarkston
The shortest distance (air line) between Aleksandrow Kujawski and Clarkston is 4,880.96 mi (7,855.15 km).
How far is Aleksandrow Kujawski from Clarkston
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:16 (07.12.2025)
Clarkston is located in Georgia, United States within 33° 48' 42.12" N -85° 45' 34.92" W (33.8117, -84.2403) coordinates. The local time in Clarkston is 13:16 (07.12.2025)
The calculated flying distance from Clarkston to Clarkston is 4,880.96 miles which is equal to 7,855.15 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Clarkston, Georgia, United States