Distance from Aleksandrow Kujawski to Clarksville
The shortest distance (air line) between Aleksandrow Kujawski and Clarksville is 4,840.16 mi (7,789.49 km).
How far is Aleksandrow Kujawski from Clarksville
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 19:16 (07.12.2025)
Clarksville is located in Tennessee, United States within 36° 34' 9.12" N -88° 39' 31.32" W (36.5692, -87.3413) coordinates. The local time in Clarksville is 12:16 (07.12.2025)
The calculated flying distance from Clarksville to Clarksville is 4,840.16 miles which is equal to 7,789.49 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Clarksville, Tennessee, United States