Distance from Aleksandrow Kujawski to Daphne
The shortest distance (air line) between Aleksandrow Kujawski and Daphne is 5,185.20 mi (8,344.77 km).
How far is Aleksandrow Kujawski from Daphne
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 15:01 (11.12.2025)
Daphne is located in Alabama, United States within 30° 37' 34.68" N -88° 7' 6.24" W (30.6263, -87.8816) coordinates. The local time in Daphne is 08:01 (11.12.2025)
The calculated flying distance from Daphne to Daphne is 5,185.20 miles which is equal to 8,344.77 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Daphne, Alabama, United States