Distance from Aleksandrow Kujawski to Dixon
The shortest distance (air line) between Aleksandrow Kujawski and Dixon is 5,698.51 mi (9,170.86 km).
How far is Aleksandrow Kujawski from Dixon
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:26 (10.12.2025)
Dixon is located in California, United States within 38° 26' 48.84" N -122° 10' 30" W (38.4469, -121.8250) coordinates. The local time in Dixon is 21:26 (09.12.2025)
The calculated flying distance from Dixon to Dixon is 5,698.51 miles which is equal to 9,170.86 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Dixon, California, United States