Distance from Aleksandrow Kujawski to Dodge City
The shortest distance (air line) between Aleksandrow Kujawski and Dodge City is 5,181.06 mi (8,338.10 km).
How far is Aleksandrow Kujawski from Dodge City
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 05:27 (10.12.2025)
Dodge City is located in Kansas, United States within 37° 45' 39.96" N -101° 58' 54.48" W (37.7611, -100.0182) coordinates. The local time in Dodge City is 22:27 (09.12.2025)
The calculated flying distance from Dodge City to Dodge City is 5,181.06 miles which is equal to 8,338.10 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Dodge City, Kansas, United States