Distance from Aleksandrow Kujawski to Draguignan
The shortest distance (air line) between Aleksandrow Kujawski and Draguignan is 853.86 mi (1,374.16 km).
How far is Aleksandrow Kujawski from Draguignan
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:52 (05.05.2025)
Draguignan is located in Var, France within 43° 32' 25.08" N 6° 28' 0.12" E (43.5403, 6.4667) coordinates. The local time in Draguignan is 00:52 (05.05.2025)
The calculated flying distance from Draguignan to Draguignan is 853.86 miles which is equal to 1,374.16 km.
Aleksandrow Kujawski, Włocławski, Poland