Distance from Aleksandrow Kujawski to Essex
The shortest distance (air line) between Aleksandrow Kujawski and Essex is 4,311.79 mi (6,939.16 km).
How far is Aleksandrow Kujawski from Essex
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:53 (10.12.2025)
Essex is located in Maryland, United States within 39° 18' 7.56" N -77° 33' 18.36" W (39.3021, -76.4449) coordinates. The local time in Essex is 00:53 (10.12.2025)
The calculated flying distance from Essex to Essex is 4,311.79 miles which is equal to 6,939.16 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Essex, Maryland, United States