Distance from Aleksandrow Kujawski to Fairfax
The shortest distance (air line) between Aleksandrow Kujawski and Fairfax is 4,365.64 mi (7,025.81 km).
How far is Aleksandrow Kujawski from Fairfax
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 07:40 (10.12.2025)
Fairfax is located in Virginia, United States within 38° 51' 11.16" N -78° 42' 1.08" W (38.8531, -77.2997) coordinates. The local time in Fairfax is 01:40 (10.12.2025)
The calculated flying distance from Fairfax to Fairfax is 4,365.64 miles which is equal to 7,025.81 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Fairfax, Virginia, United States