Distance from Aleksandrow Kujawski to Fayetteville
The shortest distance (air line) between Aleksandrow Kujawski and Fayetteville is 5,095.10 mi (8,199.76 km).
How far is Aleksandrow Kujawski from Fayetteville
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 07:40 (10.12.2025)
Fayetteville is located in Arkansas, United States within 36° 4' 17.04" N -95° 50' 2.04" W (36.0714, -94.1661) coordinates. The local time in Fayetteville is 00:40 (10.12.2025)
The calculated flying distance from Fayetteville to Fayetteville is 5,095.10 miles which is equal to 8,199.76 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Fayetteville, Arkansas, United States