Distance from Aleksandrow Kujawski to Fridley
The shortest distance (air line) between Aleksandrow Kujawski and Fridley is 4,566.29 mi (7,348.73 km).
How far is Aleksandrow Kujawski from Fridley
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:55 (10.12.2025)
Fridley is located in Minnesota, United States within 45° 5' 2.76" N -94° 44' 25.8" W (45.0841, -93.2595) coordinates. The local time in Fridley is 02:55 (10.12.2025)
The calculated flying distance from Fridley to Fridley is 4,566.29 miles which is equal to 7,348.73 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Fridley, Minnesota, United States