Distance from Aleksandrow Kujawski to Hays
The shortest distance (air line) between Aleksandrow Kujawski and Hays is 5,095.64 mi (8,200.63 km).
How far is Aleksandrow Kujawski from Hays
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:47 (11.12.2025)
Hays is located in Kansas, United States within 38° 52' 55.56" N -100° 40' 40.44" W (38.8821, -99.3221) coordinates. The local time in Hays is 17:47 (10.12.2025)
The calculated flying distance from Hays to Hays is 5,095.64 miles which is equal to 8,200.63 km.
Aleksandrow Kujawski, Włocławski, Poland