Distance from Aleksandrow Kujawski to Hazebrouck
The shortest distance (air line) between Aleksandrow Kujawski and Hazebrouck is 704.44 mi (1,133.69 km).
How far is Aleksandrow Kujawski from Hazebrouck
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:21 (05.05.2025)
Hazebrouck is located in Nord, France within 50° 43' 30" N 2° 32' 21.12" E (50.7250, 2.5392) coordinates. The local time in Hazebrouck is 06:21 (05.05.2025)
The calculated flying distance from Hazebrouck to Hazebrouck is 704.44 miles which is equal to 1,133.69 km.
Aleksandrow Kujawski, Włocławski, Poland