Distance from Aleksandrow Kujawski to Hickory
The shortest distance (air line) between Aleksandrow Kujawski and Hickory is 4,672.96 mi (7,520.40 km).
How far is Aleksandrow Kujawski from Hickory
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 02:02 (11.12.2025)
Hickory is located in North Carolina, United States within 35° 44' 27.6" N -82° 40' 39.72" W (35.7410, -81.3223) coordinates. The local time in Hickory is 20:02 (10.12.2025)
The calculated flying distance from Hickory to Hickory is 4,672.96 miles which is equal to 7,520.40 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Hickory, North Carolina, United States