Distance from Aleksandrow Kujawski to Holiday
The shortest distance (air line) between Aleksandrow Kujawski and Holiday is 5,131.42 mi (8,258.23 km).
How far is Aleksandrow Kujawski from Holiday
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 03:29 (14.12.2025)
Holiday is located in Florida, United States within 28° 11' 11.04" N -83° 15' 25.56" W (28.1864, -82.7429) coordinates. The local time in Holiday is 21:29 (13.12.2025)
The calculated flying distance from Holiday to Holiday is 5,131.42 miles which is equal to 8,258.23 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Holiday, Florida, United States