Distance from Aleksandrow Kujawski to Hudson
The shortest distance (air line) between Aleksandrow Kujawski and Hudson is 4,389.36 mi (7,063.99 km).
How far is Aleksandrow Kujawski from Hudson
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 11:15 (14.12.2025)
Hudson is located in Ohio, United States within 41° 14' 23.64" N -82° 33' 33.12" W (41.2399, -81.4408) coordinates. The local time in Hudson is 05:15 (14.12.2025)
The calculated flying distance from Hudson to Hudson is 4,389.36 miles which is equal to 7,063.99 km.
Aleksandrow Kujawski, Włocławski, Poland