Distance from Aleksandrow Kujawski to La Porte
The shortest distance (air line) between Aleksandrow Kujawski and La Porte is 5,487.68 mi (8,831.57 km).
How far is Aleksandrow Kujawski from La Porte
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:22 (12.12.2025)
La Porte is located in Texas, United States within 29° 40' 8.04" N -96° 57' 5.76" W (29.6689, -95.0484) coordinates. The local time in La Porte is 17:22 (11.12.2025)
The calculated flying distance from La Porte to La Porte is 5,487.68 miles which is equal to 8,831.57 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
La Porte, Texas, United States