Distance from Aleksandrow Kujawski to Lackawanna
The shortest distance (air line) between Aleksandrow Kujawski and Lackawanna is 4,218.60 mi (6,789.17 km).
How far is Aleksandrow Kujawski from Lackawanna
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:13 (12.12.2025)
Lackawanna is located in New York, United States within 42° 49' 5.52" N -79° 10' 3" W (42.8182, -78.8325) coordinates. The local time in Lackawanna is 18:13 (11.12.2025)
The calculated flying distance from Lackawanna to Lackawanna is 4,218.60 miles which is equal to 6,789.17 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Lackawanna, New York, United States