Distance from Aleksandrow Kujawski to Lake Oswego
The shortest distance (air line) between Aleksandrow Kujawski and Lake Oswego is 5,272.10 mi (8,484.63 km).
How far is Aleksandrow Kujawski from Lake Oswego
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:57 (12.12.2025)
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 15:57 (11.12.2025)
The calculated flying distance from Lake Oswego to Lake Oswego is 5,272.10 miles which is equal to 8,484.63 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Lake Oswego, Oregon, United States