Distance from Aleksandrow Kujawski to Le Bouscat
The shortest distance (air line) between Aleksandrow Kujawski and Le Bouscat is 1,031.94 mi (1,660.75 km).
How far is Aleksandrow Kujawski from Le Bouscat
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 12:00 (05.05.2025)
Le Bouscat is located in Gironde, France within 44° 51' 54.36" N -1° 24' 1.44" W (44.8651, -0.5996) coordinates. The local time in Le Bouscat is 12:00 (05.05.2025)
The calculated flying distance from Le Bouscat to Le Bouscat is 1,031.94 miles which is equal to 1,660.75 km.
Aleksandrow Kujawski, Włocławski, Poland