Distance from Aleksandrow Kujawski to Leopoldshohe
The shortest distance (air line) between Aleksandrow Kujawski and Leopoldshohe is 424.67 mi (683.44 km).
How far is Aleksandrow Kujawski from Leopoldshohe
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:00 (19.05.2025)
Leopoldshohe is located in Lippe, Germany within 52° 1' 0.12" N 8° 41' 60" E (52.0167, 8.7000) coordinates. The local time in Leopoldshohe is 04:00 (19.05.2025)
The calculated flying distance from Leopoldshohe to Leopoldshohe is 424.67 miles which is equal to 683.44 km.
Aleksandrow Kujawski, Włocławski, Poland