Distance from Aleksandrow Kujawski to Palmerston
The shortest distance (air line) between Aleksandrow Kujawski and Palmerston is 1,034.98 mi (1,665.63 km).
How far is Aleksandrow Kujawski from Palmerston
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 22:51 (05.06.2025)
Palmerston is located in Dublin, Ireland within 53° 21' 0" N -7° 37' 15.6" W (53.3500, -6.3790) coordinates. The local time in Palmerston is 21:51 (05.06.2025)
The calculated flying distance from Palmerston to Palmerston is 1,034.98 miles which is equal to 1,665.63 km.
Aleksandrow Kujawski, Włocławski, Poland