Distance from Aleksandrow Kujawski to Petite-Synthe
The shortest distance (air line) between Aleksandrow Kujawski and Petite-Synthe is 705.95 mi (1,136.12 km).
How far is Aleksandrow Kujawski from Petite-Synthe
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 18:21 (07.05.2025)
Petite-Synthe is located in Nord, France within 51° 1' 23.16" N 2° 21' 10.08" E (51.0231, 2.3528) coordinates. The local time in Petite-Synthe is 18:21 (07.05.2025)
The calculated flying distance from Petite-Synthe to Petite-Synthe is 705.95 miles which is equal to 1,136.12 km.
Aleksandrow Kujawski, Włocławski, Poland