Distance from Aleksandrow Kujawski to Saint-Genis-Pouilly
The shortest distance (air line) between Aleksandrow Kujawski and Saint-Genis-Pouilly is 728.01 mi (1,171.62 km).
How far is Aleksandrow Kujawski from Saint-Genis-Pouilly
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:31 (11.05.2025)
Saint-Genis-Pouilly is located in Ain, France within 46° 14' 35.88" N 6° 1' 17.04" E (46.2433, 6.0214) coordinates. The local time in Saint-Genis-Pouilly is 04:31 (11.05.2025)
The calculated flying distance from Saint-Genis-Pouilly to Saint-Genis-Pouilly is 728.01 miles which is equal to 1,171.62 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Saint-Genis-Pouilly, Ain, France