Distance from Aleksandrow Kujawski to Sassenberg
The shortest distance (air line) between Aleksandrow Kujawski and Sassenberg is 452.49 mi (728.21 km).
How far is Aleksandrow Kujawski from Sassenberg
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 01:55 (23.05.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 01:55 (23.05.2025)
The calculated flying distance from Sassenberg to Sassenberg is 452.49 miles which is equal to 728.21 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Sassenberg, Warendorf, Germany