Distance from Aleksandrow Kujawski to Sassenburg
The shortest distance (air line) between Aleksandrow Kujawski and Sassenburg is 338.24 mi (544.35 km).
How far is Aleksandrow Kujawski from Sassenburg
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:40 (23.05.2025)
Sassenburg is located in Gifhorn, Germany within 52° 31' 0.12" N 10° 37' 59.88" E (52.5167, 10.6333) coordinates. The local time in Sassenburg is 04:40 (23.05.2025)
The calculated flying distance from Sassenburg to Sassenburg is 338.24 miles which is equal to 544.35 km.
Aleksandrow Kujawski, Włocławski, Poland