Distance from Aleksandrow Kujawski to Sint-Kruis
The shortest distance (air line) between Aleksandrow Kujawski and Sint-Kruis is 664.94 mi (1,070.12 km).
How far is Aleksandrow Kujawski from Sint-Kruis
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 06:53 (28.11.2024)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 06:53 (28.11.2024)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 664.94 miles which is equal to 1,070.12 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Sint-Kruis, Arr. Brugge, Belgium