Distance from Aleksandrow Kujawski to Sotteville-les-Rouen
The shortest distance (air line) between Aleksandrow Kujawski and Sotteville-les-Rouen is 797.44 mi (1,283.35 km).
How far is Aleksandrow Kujawski from Sotteville-les-Rouen
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 23:22 (09.05.2025)
Sotteville-les-Rouen is located in Seine-Maritime, France within 49° 24' 33.12" N 1° 5' 24" E (49.4092, 1.0900) coordinates. The local time in Sotteville-les-Rouen is 23:22 (09.05.2025)
The calculated flying distance from Sotteville-les-Rouen to Sotteville-les-Rouen is 797.44 miles which is equal to 1,283.35 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Sotteville-les-Rouen, Seine-Maritime, France