Distance from Aleksandrow Kujawski to Vendin-le-Vieil
The shortest distance (air line) between Aleksandrow Kujawski and Vendin-le-Vieil is 696.60 mi (1,121.07 km).
How far is Aleksandrow Kujawski from Vendin-le-Vieil
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 21:01 (09.05.2025)
Vendin-le-Vieil is located in Pas-de-Calais, France within 50° 28' 26.04" N 2° 51' 57.96" E (50.4739, 2.8661) coordinates. The local time in Vendin-le-Vieil is 21:01 (09.05.2025)
The calculated flying distance from Vendin-le-Vieil to Vendin-le-Vieil is 696.60 miles which is equal to 1,121.07 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Vendin-le-Vieil, Pas-de-Calais, France