Distance from Aleksandrow Kujawski to Veresegyhaz
The shortest distance (air line) between Aleksandrow Kujawski and Veresegyhaz is 362.03 mi (582.63 km).
How far is Aleksandrow Kujawski from Veresegyhaz
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 01:29 (04.06.2025)
Veresegyhaz is located in Pest, Hungary within 47° 39' 1.8" N 19° 16' 58.8" E (47.6505, 19.2830) coordinates. The local time in Veresegyhaz is 01:29 (04.06.2025)
The calculated flying distance from Veresegyhaz to Veresegyhaz is 362.03 miles which is equal to 582.63 km.
Aleksandrow Kujawski, Włocławski, Poland