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      Distance from Aleksandrow Kujawski to Villeneuve-les-Maguelone

      The shortest distance (air line) between Aleksandrow Kujawski and Villeneuve-les-Maguelone is 936.49 mi (1,507.14 km).

      How far is Aleksandrow Kujawski from Villeneuve-les-Maguelone

      Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 17:35 (09.05.2025)

      Villeneuve-les-Maguelone is located in Hérault, France within 43° 31' 55.92" N 3° 51' 38.88" E (43.5322, 3.8608) coordinates. The local time in Villeneuve-les-Maguelone is 17:35 (09.05.2025)

      The calculated flying distance from Villeneuve-les-Maguelone to Villeneuve-les-Maguelone is 936.49 miles which is equal to 1,507.14 km.

      Aleksandrow Kujawski, Włocławski, Poland

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      Aleksandrow Kujawski to Wroclaw141.04 mi (226.98 km)
      Aleksandrow Kujawski to Czestochowa144.62 mi (232.74 km)
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      Aleksandrow Kujawski to Zielona Gora149.55 mi (240.68 km)
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      Aleksandrow Kujawski to Katowice180.87 mi (291.08 km)
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      Aleksandrow Kujawski to Lublin199.20 mi (320.59 km)
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      Villeneuve-les-Maguelone, Hérault, France

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