Distance from Aleksandrow Kujawski to Wavre
The shortest distance (air line) between Aleksandrow Kujawski and Wavre is 619.34 mi (996.73 km).
How far is Aleksandrow Kujawski from Wavre
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 04:47 (26.02.2025)
Wavre is located in Arr. Nivelles, Belgium within 50° 43' 0.12" N 4° 35' 60" E (50.7167, 4.6000) coordinates. The local time in Wavre is 04:47 (26.02.2025)
The calculated flying distance from Wavre to Wavre is 619.34 miles which is equal to 996.73 km.
Aleksandrow Kujawski, Włocławski, Poland
Related Distances from Aleksandrow Kujawski
Related Distances to Wavre
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| Etterbeek to Wavre | 12.43 mi (20.01 km) |
| Sint-Joost-ten-Node to Wavre | 13.21 mi (21.26 km) |
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| Koekelberg to Wavre | 15.59 mi (25.09 km) |
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| Borgerhout to Wavre | 34.90 mi (56.16 km) |
| Deurne to Wavre | 35.61 mi (57.30 km) |
| Antwerp to Wavre | 35.70 mi (57.45 km) |
| Merksem to Wavre | 37.00 mi (59.54 km) |
| Liege to Wavre | 42.83 mi (68.92 km) |
| Gent to Wavre | 44.67 mi (71.89 km) |
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