Distance from Aleksandrow Lodzki to Blankenberge
The shortest distance (air line) between Aleksandrow Lodzki and Blankenberge is 694.82 mi (1,118.20 km).
How far is Aleksandrow Lodzki from Blankenberge
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 08:22 (18.11.2024)
Blankenberge is located in Arr. Brugge, Belgium within 51° 17' 60" N 3° 7' 0.12" E (51.3000, 3.1167) coordinates. The local time in Blankenberge is 08:22 (18.11.2024)
The calculated flying distance from Blankenberge to Blankenberge is 694.82 miles which is equal to 1,118.20 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Blankenberge, Arr. Brugge, Belgium