Distance from Aleksandrow Lodzki to Cesky Tesin
The shortest distance (air line) between Aleksandrow Lodzki and Cesky Tesin is 146.28 mi (235.41 km).
How far is Aleksandrow Lodzki from Cesky Tesin
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 04:25 (19.11.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 04:25 (19.11.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 146.28 miles which is equal to 235.41 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Cesky Tesin, Moravskoslezský kraj, Czechia