Distance from Aleksandrow Lodzki to Cesson-Sevigne
The shortest distance (air line) between Aleksandrow Lodzki and Cesson-Sevigne is 959.89 mi (1,544.79 km).
How far is Aleksandrow Lodzki from Cesson-Sevigne
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:36 (19.11.2024)
Cesson-Sevigne is located in Ille-et-Vilaine, France within 48° 7' 14.88" N -2° 23' 47.04" W (48.1208, -1.6036) coordinates. The local time in Cesson-Sevigne is 23:36 (19.11.2024)
The calculated flying distance from Cesson-Sevigne to Cesson-Sevigne is 959.89 miles which is equal to 1,544.79 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Cesson-Sevigne, Ille-et-Vilaine, France