Distance from Aleksandrow Lodzki to Chatellerault
The shortest distance (air line) between Aleksandrow Lodzki and Chatellerault is 909.50 mi (1,463.70 km).
How far is Aleksandrow Lodzki from Chatellerault
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 01:36 (20.11.2024)
Chatellerault is located in Vienne, France within 46° 49' 4.08" N 0° 32' 45.96" E (46.8178, 0.5461) coordinates. The local time in Chatellerault is 01:36 (20.11.2024)
The calculated flying distance from Chatellerault to Chatellerault is 909.50 miles which is equal to 1,463.70 km.
Aleksandrow Lodzki, Łódzki, Poland