Distance from Aleksandrow Lodzki to Court-Saint-Etienne
The shortest distance (air line) between Aleksandrow Lodzki and Court-Saint-Etienne is 641.79 mi (1,032.86 km).
How far is Aleksandrow Lodzki from Court-Saint-Etienne
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 10:29 (18.11.2024)
Court-Saint-Etienne is located in Arr. Nivelles, Belgium within 50° 37' 59.88" N 4° 34' 0.12" E (50.6333, 4.5667) coordinates. The local time in Court-Saint-Etienne is 10:29 (18.11.2024)
The calculated flying distance from Court-Saint-Etienne to Court-Saint-Etienne is 641.79 miles which is equal to 1,032.86 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Court-Saint-Etienne, Arr. Nivelles, Belgium