Distance from Aleksandrow Lodzki to Crepy-en-Valois
The shortest distance (air line) between Aleksandrow Lodzki and Crepy-en-Valois is 741.11 mi (1,192.70 km).
How far is Aleksandrow Lodzki from Crepy-en-Valois
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:34 (20.11.2024)
Crepy-en-Valois is located in Oise, France within 49° 14' 3.84" N 2° 53' 15" E (49.2344, 2.8875) coordinates. The local time in Crepy-en-Valois is 03:34 (20.11.2024)
The calculated flying distance from Crepy-en-Valois to Crepy-en-Valois is 741.11 miles which is equal to 1,192.70 km.
Aleksandrow Lodzki, Łódzki, Poland