Distance from Aleksandrow Lodzki to Heist-op-den-Berg
The shortest distance (air line) between Aleksandrow Lodzki and Heist-op-den-Berg is 629.08 mi (1,012.41 km).
How far is Aleksandrow Lodzki from Heist-op-den-Berg
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:09 (05.04.2025)
Heist-op-den-Berg is located in Arr. Mechelen, Belgium within 51° 4' 59.88" N 4° 43' 0.12" E (51.0833, 4.7167) coordinates. The local time in Heist-op-den-Berg is 02:09 (05.04.2025)
The calculated flying distance from Heist-op-den-Berg to Heist-op-den-Berg is 629.08 miles which is equal to 1,012.41 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Heist-op-den-Berg, Arr. Mechelen, Belgium