Distance from Aleksandrow Lodzki to Jasper
The shortest distance (air line) between Aleksandrow Lodzki and Jasper is 4,791.58 mi (7,711.30 km).
How far is Aleksandrow Lodzki from Jasper
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 00:37 (06.12.2025)
Jasper is located in Indiana, United States within 38° 23' 35.88" N -87° 3' 35.28" W (38.3933, -86.9402) coordinates. The local time in Jasper is 18:37 (05.12.2025)
The calculated flying distance from Jasper to Jasper is 4,791.58 miles which is equal to 7,711.30 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Jasper, Indiana, United States