Distance from Aleksandrow Lodzki to Lackawanna
The shortest distance (air line) between Aleksandrow Lodzki and Lackawanna is 4,280.98 mi (6,889.57 km).
How far is Aleksandrow Lodzki from Lackawanna
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 02:46 (06.12.2025)
Lackawanna is located in New York, United States within 42° 49' 5.52" N -79° 10' 3" W (42.8182, -78.8325) coordinates. The local time in Lackawanna is 20:46 (05.12.2025)
The calculated flying distance from Lackawanna to Lackawanna is 4,280.98 miles which is equal to 6,889.57 km.
Aleksandrow Lodzki, Łódzki, Poland
Related Distances from Aleksandrow Lodzki
Lackawanna, New York, United States