Distance from Aleksandrow Lodzki to Le Haillan
The shortest distance (air line) between Aleksandrow Lodzki and Le Haillan is 1,030.84 mi (1,658.98 km).
How far is Aleksandrow Lodzki from Le Haillan
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 11:45 (20.11.2024)
Le Haillan is located in Gironde, France within 44° 52' 18.12" N -1° 19' 23.16" W (44.8717, -0.6769) coordinates. The local time in Le Haillan is 11:45 (20.11.2024)
The calculated flying distance from Le Haillan to Le Haillan is 1,030.84 miles which is equal to 1,658.98 km.
Aleksandrow Lodzki, Łódzki, Poland